The fizzbuzz program in python

The fizzbuzz program is to validate your python knowledge of conditions and loops.

It states that to loop over the numbers between 1 to 100, if the current number is perfectly divisible by 3 then print ‘fizz’.

Else if the number is perfectly divisible by 5 then print ‘buzz’. Finally, if the number is perfectly divisible by both 3 and 5 then print ‘fizzbuzz’, rest all cases just print the number itself.

# Algorithm
F(N) = "fizzbuzz" # if N % 3 == 0 && N % 5 == 0
     = "buzz" # if N % 5 == 0
     = "fizz" # if N % 3 == 0
     = N  # for all other cases

fizzbuzz program in python

# fizzbuzz.py
# prints fizz if divisible by only 3
# print buzz if divisible by only 5
# print fizzbuzz if divisible by both 5 and 3.
def fizzBuzzFunc(num):
    if num % (3*5) == 0:
        return 'fizzbuzz'
    elif num % 5 == 0:
        return 'buzz'
    elif num % 3 == 0:
        return 'fizz'
    else:
        return str(num)
    
# fizzbuzz program to print 1 to 100.
for i in range(1, 100):
    print(fizzBuzzFunc(i))

The above program takes a range of 1 to 100, you can always change the range by providing different values in the program. The output of the above program is as follows.

# Output
$python fizzbuzz.py
1
2
fizz
4
buzz
fizz
7
8
fizz
buzz
11
fizz
13
14
fizzbuzz
16
17
fizz
19
buzz
fizz
22
23
fizz
buzz
26
fizz
28
29
fizzbuzz
31
32
fizz
34
buzz
fizz
37
38
fizz
buzz
41
fizz
43
44
fizzbuzz
46
47
fizz
49
buzz
fizz
52
53
fizz
buzz
56
fizz
58
59
fizzbuzz
61
62
fizz
64
buzz
fizz
67
68
fizz
buzz
71
fizz
73
74
fizzbuzz
76
77
fizz
79
buzz
fizz
82
83
fizz
buzz
86
fizz
88
89
fizzbuzz
91
92
fizz
94
buzz
fizz
97
98
fizz

The program runs with a linear (O(N)) time complexity. This is all about the fizzbuzz program in python. Happy learning!.